Evaluate ((16-14)^3+(13-18)^2)÷((7-8)^2)*(9-20)

$({(16 - 14)}^{3} + {(13 - 18)}^{2}) \div {(7 - 8)}^{2} \cdot (9 - 20)$

Step 1

Simplify the numerator.

Subtract $14$ from $16$ .

$(2^{3} + {(13 - 18)}^{2}) \div {(7 - 8)}^{2} \cdot (9 - 20)$

Raise $2$ to the power of $3$ .

$(8 + {(13 - 18)}^{2}) \div {(7 - 8)}^{2} \cdot (9 - 20)$

Subtract $18$ from $13$ .

$(8 + {(- 5)}^{2}) \div {(7 - 8)}^{2} \cdot (9 - 20)$

Raise $- 5$ to the power of $2$ .

$(8 + 25) \div {(7 - 8)}^{2} \cdot (9 - 20)$

Add $8$ and $25$ .

$33 \div {(7 - 8)}^{2} \cdot (9 - 20)$

Step 2

Simplify the denominator.

Subtract $8$ from $7$ .

$33 \div {(- 1)}^{2} \cdot (9 - 20)$

Raise $- 1$ to the power of $2$ .

$33 \div 1 \cdot (9 - 20)$

Step 3

Simplify the expression.

Divide $33$ by $1$ .

$33 \cdot (9 - 20)$

Subtract $20$ from $9$ .

$33 \cdot - 11$

Multiply $33$ by $- 11$ .

$- 363$