Utilize ourHarmonic sequence calculator tool for finding the sum of n terms of harmonic sequence when n=6, a=2, and d = 2 easily and quickly. So that you will get the result of 1/42.0.
Sn = `(1/d)*ln( (2*a+(2*n-1)*d)/(2*a-d) )`
a = 2
n = 6
d = 2
Put values into formulaS6 = `(1/d)*ln( (2*a+(2*n-1)*d)/(2*a-d) )`
S6 = `(1/2)*ln( (2*2+(2*6-1)*2)/(2*2-2) )`
S6 = 1.28247
Following are the step by step process to find the sum of N terms in a harmonic sequence easily by hand.
1. How to find the sum of n terms of harmonic sequence for a = 2, n=6, and d=2?
As we know that the reciprocal of arithmetic progression is the harmonic sequence, find the sum of n terms of arithmetic progression and then make a reciprocal. So that you will get the sum of n terms of harmonic sequence.
2. What is the sum of n terms of harmonic sequence for a = 2, n=6, and d=2?
sum of n terms of harmonic sequence for a = 2, n=6, and d=2 is 1/42.0.
3. Where can I find the step by step process for sum of n terms of harmonic sequence a = 2, n=6, and d=2?
You can find the detailed steps for sum of n terms of harmonic sequence a = 2, n=6, and d=2 on our page.