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Find the Sum of n terms of Harmonic Sequence a = 5, n=7, and d=4

Utilize ourHarmonic sequence calculator tool for finding the sum of n terms of harmonic sequence when n=7, a=5, and d = 4 easily and quickly. So that you will get the result of 1/119.0.

First term [a]:
common difference[d]:
Total terms[n]:

Steps to find sum of n terms of harmonic sequence:

sum of n terms of harmonic sequence formula:-

Sn = `(1/d)*ln( (2*a+(2*n-1)*d)/(2*a-d) )`


where:
  • sn is the sum of n terms
  • a is first term
  • n is total number of terms
  • d is common difference
Input values are:-

a = 5

n = 7

d = 4

Put values into formula

S7 = `(1/d)*ln( (2*a+(2*n-1)*d)/(2*a-d) )`

S7 = `(1/4)*ln( (2*5+(2*7-1)*4)/(2*5-4) )`

S7 = 0.58384

How to Find the Sum of N terms of Harmonic Sequence of a = 5, n=7, and d=4?

Following are the step by step process to find the sum of N terms in a harmonic sequence easily by hand.

  • Firstly, Write down the values that were given in the problem, such as a = 5, n=7, and d=4.
  • As we know that arithmetic progression is the reciprocal of harmonic progression.
  • Apply the formula of sum of n term of Arithmetic Progression, i.e., Sn = n/2[2a + (n − 1) × d]
  • Substitute the values in the formula, i.e., Sn = 7/2[2*5 + (7 − 1) × 4].
  • Simplify the equation, i.e., Sn = 7/2[2*5 + (7-1) × 4] = 119.0
  • At last , the sum of n terms of Arithmetic progression is 119.0.
  • Finally, the result of sum of n terms of Harmonic sequence is 1/119.0

Example for Finding Sum of n terms of Harmonic Sequence

Sum of n terms of HP when a = 1, d = 4 and n = 9
Sum of n terms of HP when a = 3, d = 2 and n = 9
Sum of n terms of HP when a = 5, d = 3 and n = 10
Sum of n terms of HP when a = 2, d = 3 and n = 6
Sum of n terms of HP when a = 1, d = 3 and n = 6
Sum of n terms of HP when a = 5, d = 2 and n = 6
Sum of n terms of HP when a = 4, d = 4 and n = 10
Sum of n terms of HP when a = 1, d = 2 and n = 11
Sum of n terms of HP when a = 2, d = 2 and n = 6
Sum of n terms of HP when a = 4, d = 3 and n = 7

FAQs on Computing Sum of N terms for Harmonic Sequence for a = 5, n=7, and d=4

1. How to find the sum of n terms of harmonic sequence for a = 5, n=7, and d=4?

As we know that the reciprocal of arithmetic progression is the harmonic sequence, find the sum of n terms of arithmetic progression and then make a reciprocal. So that you will get the sum of n terms of harmonic sequence.

2. What is the sum of n terms of harmonic sequence for a = 5, n=7, and d=4?

sum of n terms of harmonic sequence for a = 5, n=7, and d=4 is 1/119.0.

3. Where can I find the step by step process for sum of n terms of harmonic sequence a = 5, n=7, and d=4?

You can find the detailed steps for sum of n terms of harmonic sequence a = 5, n=7, and d=4 on our page.