Utilize ourHarmonic sequence calculator tool for finding the sum of n terms of harmonic sequence when n=7, a=5, and d = 4 easily and quickly. So that you will get the result of 1/119.0.
Sn = `(1/d)*ln( (2*a+(2*n-1)*d)/(2*a-d) )`
a = 5
n = 7
d = 4
Put values into formulaS7 = `(1/d)*ln( (2*a+(2*n-1)*d)/(2*a-d) )`
S7 = `(1/4)*ln( (2*5+(2*7-1)*4)/(2*5-4) )`
S7 = 0.58384
Following are the step by step process to find the sum of N terms in a harmonic sequence easily by hand.
1. How to find the sum of n terms of harmonic sequence for a = 5, n=7, and d=4?
As we know that the reciprocal of arithmetic progression is the harmonic sequence, find the sum of n terms of arithmetic progression and then make a reciprocal. So that you will get the sum of n terms of harmonic sequence.
2. What is the sum of n terms of harmonic sequence for a = 5, n=7, and d=4?
sum of n terms of harmonic sequence for a = 5, n=7, and d=4 is 1/119.0.
3. Where can I find the step by step process for sum of n terms of harmonic sequence a = 5, n=7, and d=4?
You can find the detailed steps for sum of n terms of harmonic sequence a = 5, n=7, and d=4 on our page.