Utilize our**Harmonic sequence calculator** tool for finding the sum of n terms of harmonic sequence when n=7, a=4, and d = 3 easily and quickly. So that you will get the result of 1/91.0.

S_{n} = `(1/d)*ln( (2*a+(2*n-1)*d)/(2*a-d) )`

- s
_{n}is the sum of n terms - a is first term
- n is total number of terms
- d is common difference

a = 4

n = 7

d = 3

S_{7} = `(1/d)*ln( (2*a+(2*n-1)*d)/(2*a-d) )`

S_{7} = `(1/3)*ln( (2*4+(2*7-1)*3)/(2*4-3) )`

**S _{7} = 0.7469**

Following are the step by step process to find the sum of N terms in a harmonic sequence easily by hand.

- Firstly, Write down the values that were given in the problem, such as a = 4, n=7, and d=3.
- As we know that arithmetic progression is the reciprocal of harmonic progression.
- Apply the formula of sum of n term of Arithmetic Progression, i.e., Sn = n/2[2a + (n − 1) × d]
- Substitute the values in the formula, i.e., Sn = 7/2[2*4 + (7 − 1) × 3].
- Simplify the equation, i.e., Sn = 7/2[2*4 + (7-1) × 3] = 91.0
- At last , the sum of n terms of Arithmetic progression is 91.0.
- Finally, the result of sum of n terms of Harmonic sequence is 1/91.0

**1. How to find the sum of n terms of harmonic sequence for a = 4, n=7, and d=3?**

As we know that the reciprocal of arithmetic progression is the harmonic sequence, find the sum of n terms of arithmetic progression and then make a reciprocal. So that you will get the sum of n terms of harmonic sequence.

**2. What is the sum of n terms of harmonic sequence for a = 4, n=7, and d=3?**

sum of n terms of harmonic sequence for a = 4, n=7, and d=3 is 1/91.0.

**3. Where can I find the step by step process for sum of n terms of harmonic sequence a = 4, n=7, and d=3?**

You can find the detailed steps for sum of n terms of harmonic sequence a = 4, n=7, and d=3 on our page.