# Find the Sum of n terms of Geometric Sequence a = 4, n = 8, and r =2

Try our Geometric Sequence Calculator to quickly obtain the Sum of n terms of Geometric Sequence a = 4, n = 8, and r =2 i.e. 1020.0 in the blink of an eye.

First term [a]:
common ratio[r]:
Total terms[n]:

### Steps to find sum of n terms of geometric sequence:

sum of n terms of geometric sequence formula:-

where:
• sn is the sum of n terms
• a is first term
• n is total number of terms
• r is common ratio
Input values are:-

a = 4

n = 8

r = 2

Put values into formula

S8 = a*(r^n-1)/(r-1)

S8 = 4*(2^8-1)/(2-1)

S8 = 1020.0

## Steps for finding the Sum of n terms of Geometric Sequence a = 4, n = 8, and r =2?

Follow the detailed steps listed below to find the Sum of n terms of Geometric Sequence a = 4, n = 8, and r = 2 to make your calculations faster.

• The initial step is to find out the First Term of Sequence a = 4, Common Ratio r = 2 and n = 8
• Later, substitute the given values in the Sum of n terms in G.P Formula i.e. Sn = a[(rn-1)/(r-1)] if r > 1 and r ≠ 1 or Sn = a[(1 – rn)/(1 – r)] if r < 1 and r ≠ 1
• As in the given case common ratio r is greater than 1 we will use the formula Sn = a[(rn-1)/(r-1)] and substitute given values i.e. S6 = 4[(28-1)/(2-1)]
• Simplifying further we have the Sum of n terms of Geometric Sequence S6= 1020.0.

## FAQs on Sum of n terms in G.P for a = 4, n = 8, and r =2

1. How to find the Sum of n terms in G.P?

Sum of n terms in G.P can be found by using the formulas Sn = a[(rn-1)/(r-1)] if r > 1 and r ≠ 1 or Sn = a[(1 – rn)/(1 – r)] if r < 1 and r ≠ 1.

2. What is the sum of n terms in Geometric Sequence a = 4, n = 8, and r =2?

Sum of n terms in the Geometric Sequence a = 4, n = 8, and r =2 is 1020.0.

3. How to find the sum of n terms in Geometric Sequence a = 4, n = 8, and r =2 quickly?

You can take help from our geometric sequence calculator in order to find out the sum of n terms in Geometric Sequence a = 4, n = 8, and r =2 quickly.