# Find the Sum of n terms of Geometric Sequence a = 3, n = 11, and r =4

Try our Geometric Sequence Calculator to quickly obtain the Sum of n terms of Geometric Sequence a = 3, n = 11, and r =4 i.e. 4194303.0 in the blink of an eye.

First term [a]:
common ratio[r]:
Total terms[n]:

### Steps to find sum of n terms of geometric sequence:

sum of n terms of geometric sequence formula:-

where:
• sn is the sum of n terms
• a is first term
• n is total number of terms
• r is common ratio
Input values are:-

a = 3

n = 11

r = 4

Put values into formula

S11 = a*(r^n-1)/(r-1)

S11 = 3*(4^11-1)/(4-1)

S11 = 4194303.0

## Steps for finding the Sum of n terms of Geometric Sequence a = 3, n = 11, and r =4?

Follow the detailed steps listed below to find the Sum of n terms of Geometric Sequence a = 3, n = 11, and r = 4 to make your calculations faster.

• The initial step is to find out the First Term of Sequence a = 3, Common Ratio r = 4 and n = 11
• Later, substitute the given values in the Sum of n terms in G.P Formula i.e. Sn = a[(rn-1)/(r-1)] if r > 1 and r ≠ 1 or Sn = a[(1 – rn)/(1 – r)] if r < 1 and r ≠ 1
• As in the given case common ratio r is greater than 1 we will use the formula Sn = a[(rn-1)/(r-1)] and substitute given values i.e. S6 = 3[(411-1)/(4-1)]
• Simplifying further we have the Sum of n terms of Geometric Sequence S6= 4194303.0.

## FAQs on Sum of n terms in G.P for a = 3, n = 11, and r =4

1. How to find the Sum of n terms in G.P?

Sum of n terms in G.P can be found by using the formulas Sn = a[(rn-1)/(r-1)] if r > 1 and r ≠ 1 or Sn = a[(1 – rn)/(1 – r)] if r < 1 and r ≠ 1.

2. What is the sum of n terms in Geometric Sequence a = 3, n = 11, and r =4?

Sum of n terms in the Geometric Sequence a = 3, n = 11, and r =4 is 4194303.0.

3. How to find the sum of n terms in Geometric Sequence a = 3, n = 11, and r =4 quickly?

You can take help from our geometric sequence calculator in order to find out the sum of n terms in Geometric Sequence a = 3, n = 11, and r =4 quickly.