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Simplify (11(9^2-5^2))÷(2^2)+8

$11 (9^{2} - 5^{2}) \div 2^{2} + 8$

Step 1

Simplify each term.

Rewrite the division as a fraction.

$\frac{11 (9^{2} - 5^{2})}{2^{2}} + 8$

Simplify the numerator.

Raise $9$ to the power of $2$ .

$\frac{11 (81 - 5^{2})}{2^{2}} + 8$

Raise $5$ to the power of $2$ .

$\frac{11 (81 - 1 \cdot 25)}{2^{2}} + 8$

Multiply $- 1$ by $25$ .

$\frac{11 (81 - 25)}{2^{2}} + 8$

Subtract $25$ from $81$ .

$\frac{11 \cdot 56}{2^{2}} + 8$

$\frac{11 \cdot 56}{2^{2}} + 8$

Raise $2$ to the power of $2$ .

$\frac{11 \cdot 56}{4} + 8$

Multiply $11$ by $56$ .

$\frac{616}{4} + 8$

Divide $616$ by $4$ .

$154 + 8$

$154 + 8$

Step 2

Add $154$ and $8$ .

$162$

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